What is the ratio of (a) gram atoms and (b) weights of the metals liberated during the electrolysis of fused sodium fluroide, magnesium fluoride and aluminium fluoride connected in a series?

Explanation

`Na^(+) e^(-) rarr Na, Mg^(2+) +2e^(-) rarr Mg` and `Al^(3+)+3e^(-) rarr Al`
Ratio of gram atoms of metals liberated using one Faraday
`= 1/1:1/2:1/3=6:3:2`,
`w_(1) :w_(2):w_(3)=E_(1):E_(2):E_(3)`
Ratio of weights of metals liberated `=23:12:9`