During the electrolysis of fused potassium chloride at platinum electrodes, 0.25 gram atom of metal is liberated. What would be the volume of chlorine that can be collected in the experiment at STP?

Explanation

Reaction at cathode,
`K^(+)+e^(-) rarr K` and
at anode, `2Cl^(-) rarr 2e^(-) +Cl_(2)`.
For 0.25 gram atom of potassium liberated, moles of chlorinereleased `=0.125`.
Volume of chlorine released in the experiment at STP
`=0.125xx22.4=2.8 L`.