At `25^(@)C`, the reduction potential of hydrogen electrode is `-0.118` V at 1 atm. What is he pH of acid solution used for the construction of the electrode ?

Explanation

`E=E^(@)+(0.059)/(n) log C`
(or) `E =E^(@)+(0.059)/(2) log [H^(+)]`
`-0.118=0.059 log [H^(+)]` (or)
`-log[H^(+)] =2 , pH=2`.