A cell is constructed `Pb^(2+)` Pb and `Ni^(2+)`, Ni electrodes. If `E^(@)` values of Pb and Ni electrodes are respectively -0.13 and -0.25V, write (a) the cell reaction and (b) cell notation.

Explanation

Reduction potential of Ni electrode is less and hence it reduces `Pb^(2+)` ions.
The cell reaction is written as, `Ni+Pb^(2+) rarr Pb+Ni^(2+)`
The oxidation half reaction is, `Ni rarr Ni^(2+) +2e^(-)`
The reduction half reaction is , `Pb^(2+)+2e^(-) rarr Pb`
The cell is written as, `Ni, Ni_((aq))^(2+) //Pb_((aq))^(2+), Pb`.