Iron rod is immersed in NaCl solution such that half its length is exposed to air and the other half immersed in NaCl solution. Which part is corroded and why ?

Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. The platinum electrodes were immersed in a solution of cupric sulphate (CuSO_4) and electric current is passed through the solution. After sometimes, it was observed that the colour of copper sulphate disappeared with evolution of a gas at the electrode. The colourless solution contains.

A cylindrical rod with one end in steam and other end in ice results in melting of 0.1 g of ice per second If the rod is replaced by another with half the length, double the radius of first and if the conductivity of material of second is 1/4 of first, the rate at which ice melts is (in g/s)

An object of density 2000kg- m^(-3) is hung from a thin light wire . The fundamental frequency of the transverse waves in the wire is 2009 Hz. If the object if immersed in water such that half of its volume is submerged, the the fundamental frequency of the transverse waves in the wire is

A cylindrical tube, open at both ends, has a fundamental frequency f_(0) in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is

When an iron nail is immersed in copper sulphate solution, the colour of solution changes from blue to green colour, The substance formed is the solution is_________

Why do we use KOH solution in Mohl's half-leaf experiment ?