Home
Class 12
CHEMISTRY
The conductivity of 0.001 M acetic acid ...

The conductivity of 0.001 M acetic acid is `5 xx 10^(-5)` S `cm^(-1)` and `^^""^(0)` is 390.5 S `cm^(2) "mol" ^(-1)` then the calculated value of dissociation constant of acetic acid would be

A

`81.78xx10^(-4)`

B

`81.78xx10^(-5)`

C

`18.78xx10^(-6)`

D

`18.78xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise Exercise -2 (Nernst equation and EMF)|19 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE EXERCISE|55 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise Exercise -2|1 Videos

  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos

  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos