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The conductivity of 0.001 M acetic acid ...

The conductivity of 0.001 M acetic acid is `5 xx 10^(-5)` S `cm^(-1)` and `^^""^(0)` is 390.5 S `cm^(2) "mol" ^(-1)` then the calculated value of dissociation constant of acetic acid would be

A

`81.78xx10^(-4)`

B

`81.78xx10^(-5)`

C

`18.78xx10^(-6)`

D

`18.78xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
C
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