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Two putty balls of equal mass moving with equal velocity in mutually perpendicular direction, stick together after collision. If the balls were initially moving with a velocity of `45sqrt(2)jms^(-1)` each, the velocity of their combined mass after collision is

A

`45 sqrt(2)ms^(-1)`

B

`45ms^(-1)`

C

`90ms^(-1)`

D

`22.5 sqrt(2)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B


Initial momentum `vec(P)= m 45 sqrt2 hat(i) + m 45 sqrt2 hat(j) rArr |vec(P)| = m xx 90`
Final momentum `2m xx V`
By conservation of momentum `2m xx V= m xx 90`
`therefore V= 45m//s`
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