A neutron having a mass of `1.67 xx 10^(-27) kg` and moving at `10^(8) m//s`collides with a deuteron at rest and sticks to it. If the mass of the deuteron is `3.33 xx 10^(-27) kg` then the speed of the combination is

Options

A. `2.56 xx 10^(3)m//s`
B. `2.98 xx 10^(5) m//s`
C. `3.33 xx 10^(7) m//s`
D. `5.01 xx 10^(9) m//s`

Answer

C

Explanation

According to law of conservation of momentum. Momentum of neutron= Momentum of combination
`rArr 1.67 xx 10^(-27) xx 10^(8)= (1.67 xx 10^(-27) + 3.34 xx 10^(-27))v`
`therefore v= 3.33 xx 10^(7) m//s`