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A body of mass 4 kg moving with velocity...

A body of mass `4 kg` moving with velocity `12 m//s` collides with another body of mass `6 kg` at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A

Zero

B

288 J

C

172.8 J

D

144 J

Text Solution

Verified by Experts

The correct Answer is:
C
Loss in K.E. `= (m_(1)m_(2))/(2(m_(1) + m_(2)))(u_(1) -u_(2))^(2)`
`= (4 xx 6)/(2 xx 10) xx (12-0)^(2) = 172.8 J`
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