A bomb of mass 3 m kg explodes into two pieces of mass m kg and m kg . If the velocity of m kg mass is 16 m / s , the total kinetic energy released in the explosion is

Options

A. 192 ml
B. 96 ml
C. 384 ml
D. 768 ml

Answer

A

Explanation

By the conservation of momentum ` m_A v_A = m_B v_B `
` rArr m xx 16 = 2m xx v_B rArr v_B = 8 m//s `
Kinetic energy of system `= (1)/(2) m_A v_A^(2) +(1)/(2) m_Bv_B^(2) `
`= (1)/(2) xx m xx (16)^(2) + (1)/(2) xx (2m ) xx 8 ^(2) = 192 mJ `