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A neutron travelling with a velocity v a...

A neutron travelling with a velocity `v` and kinetic energy `E` collides perfectly elastically head on with the nucleus of an atom of mass number `A` at rest. The fraction of the total kinetic energy retained by the neutron is

A

`((A-1)/(A+1))^(2) `

B

` ((A+1)/(A-1))^(2) `

C

` ((A-1)/(A))^(2) `

D

` ((A+1)/(A))^(2) `

Text Solution

Verified by Experts

The correct Answer is:
A


` ((Delta K)/( K)) _(" retained") =((m_1-m_2)/(m_1+m_2) ) ^(2) = ((1-A)/(1+A))^(2) `
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