Find the equation of the normals to the ...

Find the equation of the normals to the circle `x^2+y^2-8x-2y+12=0` at the point whose ordinate is `-1`

A

`2x-y-7=0, 2x+y-9=0`

B

`2x+y-7=0, 2x+y+9=0`

C

`2x+y+7=0, 2x+y+9=0`

D

None of these

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The correct Answer is:

A

If ordinate is - 1 then abscissa may be 3 or 5. Hence normal are lines passing through (4, 1) and (3, -1) and other passes through (4, 1) (5, -1)

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