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the line x/a-y/b=1 cuts the x-axes at P....

the line `x/a-y/b=1` cuts the `x`-axes at `P`.the equation of the line passes through point `P` and perpendicular to the line is:

A

`x+y=ab`

B

`x+y=a+b`

C

`ax+by=a^(2)`

D

`bx+ay=b^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Line perpendicular to the given line `(x)/(a)-(y)/(b)=1`
`(x)/(b)+(y)/(a)+lambda=0`
According to the question, line (i) is passing through the point P(a, 0)
`(a)/(b)+0+lambda=0`
`lambda=(-a)/(b)`
Put the value of `lambda` in equation (i), we get `(x)/(b)+(y)/(a)-(a)/(b)=0`
`ax+by=a^(2)`
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