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The equations of the sides of a triangle...

The equations of the sides of a triangle are `x-3y=0,4x+3y=5,3x+y=0.` The line `3x-4y=0` passes through (A) Incentre (B) Centroid (C) Orthocentre (D) Circumcentre

A

the incentre

B

the centroid

C

the orthocentre

D

the circumcentre

Text Solution

Verified by Experts

The correct Answer is:
C
Two sides `x – 3y = 0` and `3x + y = 0` are perpendicular to each other. Therefore, its orthocentre is the point of intersection of `x – 3y = 0` and `3x + y = 0 i.e., (0, 0)`, So the line `3x – 4y = 0` passes through the orthocentre of triangle.
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