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The number of common tangents to the cir...

The number of common tangents to the circle `x^(2)+y^(2)-2x-4y-4=0 and x^(2)+y^(2)+4x+8y-5=0` is _________.

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To find the number of common tangents to the two given circles, we will follow these steps: ### Step 1: Write the equations of the circles in standard form. The equations of the circles are given as: 1. \( x^2 + y^2 - 2x - 4y - 4 = 0 \) 2. \( x^2 + y^2 + 4x + 8y - 5 = 0 \) We will complete the square for both circles. **For the first circle:** \[ x^2 - 2x + y^2 - 4y = 4 \] Completing the square: \[ (x - 1)^2 - 1 + (y - 2)^2 - 4 = 4 \] \[ (x - 1)^2 + (y - 2)^2 = 9 \] This gives us: - Center \( C_1 = (1, 2) \) - Radius \( r_1 = 3 \) **For the second circle:** \[ x^2 + 4x + y^2 + 8y = 5 \] Completing the square: \[ (x + 2)^2 - 4 + (y + 4)^2 - 16 = 5 \] \[ (x + 2)^2 + (y + 4)^2 = 25 \] This gives us: - Center \( C_2 = (-2, -4) \) - Radius \( r_2 = 5 \) ### Step 2: Calculate the required values. Now we will calculate the following values: 1. \( |r_1 - r_2| \) 2. \( r_1 + r_2 \) 3. The distance between the centers \( C_1 \) and \( C_2 \). **Calculating \( |r_1 - r_2| \):** \[ |r_1 - r_2| = |3 - 5| = 2 \] **Calculating \( r_1 + r_2 \):** \[ r_1 + r_2 = 3 + 5 = 8 \] **Calculating the distance between the centers \( C_1 \) and \( C_2 \):** Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the values: \[ d = \sqrt{((-2) - 1)^2 + ((-4) - 2)^2} = \sqrt{(-3)^2 + (-6)^2} = \sqrt{9 + 36} = \sqrt{45} \] ### Step 3: Analyze the conditions for common tangents. We have: - \( |r_1 - r_2| = 2 \) - \( r_1 + r_2 = 8 \) - \( d = \sqrt{45} \) Now we need to check the conditions for the number of common tangents: 1. If \( d > r_1 + r_2 \): 4 common tangents 2. If \( d = r_1 + r_2 \): 3 common tangents 3. If \( |r_1 - r_2| < d < r_1 + r_2 \): 2 common tangents 4. If \( d = |r_1 - r_2| \): 1 common tangent 5. If \( d < |r_1 - r_2| \): 0 common tangents ### Step 4: Compare the values. We know: - \( |r_1 - r_2| = 2 \) - \( r_1 + r_2 = 8 \) - \( d = \sqrt{45} \approx 6.71 \) Now we check: - \( 2 < \sqrt{45} < 8 \) This means that the distance between the centers is greater than the difference of the radii and less than the sum of the radii. ### Conclusion: Thus, the number of common tangents is **2**.

To find the number of common tangents to the two given circles, we will follow these steps: ### Step 1: Write the equations of the circles in standard form. The equations of the circles are given as: 1. \( x^2 + y^2 - 2x - 4y - 4 = 0 \) 2. \( x^2 + y^2 + 4x + 8y - 5 = 0 \) We will complete the square for both circles. ...
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