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The acceleration due to gravity near the...

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

A

`rho R`

B

`rho R^(-1)`

C

`rho^(-1)R^(-2)`

D

`rhoR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`g=(GM)/(R^(2))=(G)/(R^(2))(rho((4)/(3)piR^(3)))=(4)/(3)GpirhoR`
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