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Z(2) undergo disproportion in an alkali...

`Z_(2)` undergo disproportion in an alkaline medium into a mixture of `Z^(-)` and `ZO_(3)^(-)`. Equivalent mass of `Z_(2)` in the reaction is: [given that atomic mass of Z is 80 gm/mol]

A

96

B

48

C

64

D

32

Text Solution

Verified by Experts

The correct Answer is:
A
It is a disproportionation redox reaction
`3Z_(2) rarr 5Z^(-) + ZO_(3)^(-)` ……..n factor of `Z_(2)= 5//3`
`therefore` Equivalent mass of `Z_(2)= (M^(@))/(5//3) = (3)/(5) [160] = 96`
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