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Identify me : I am a type of cell divisi...

Identify me : I am a type of cell division, significant during sexual reproduction and helping to maintain constant chromosome number generation after generation in particular species.

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Meiosis
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How is the number of chromosomes and the DNA content maintained constant generation after generation sexually reproducing organisms ?

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Give scientific reasons for the following statements: Each new generation through sexual mode of reproduction will end up in equal number of chromosomes and the DNA content instead of double to its parents.

A few statements with regard to sexual reproduction are give below : (i) Sexual reproduction does not always require two individuals. (ii) Sexual reproduction generally involves gametic fusion. (iii) Meiosis never occurs during sexual reproduction. (iv) External fertilisation is a rule during sexual reproduction. Choose the correct statements from the options below :

Nucleophilic substitution reactions generally expressed as Nu^(-) +R-L rarr R-Nu +L^(-) Where Nu^(-) rarr Nucleophile , R-L rarr substrate, L rarr leaving group The best leaving groups are those that become the most stable ions after they depart. since most leaving group leave as a negatibe ion, the best leaving groups are those ions that stabilize a negative charge most effectively. A good leaving group should be (a) electron-withdrawing to polarize the carbon (b) stable once it has left (not a strong base) (c) polarise able to maintain partial bonding with the carbon in the transition state (both S_(N)1 and S_(N)2) . This bonding helps to stabilise the transition state and reduces the activation energy. (I) CI^(-) (II) CH_(3)O^(-) (III) CH_(3)S^(-) (IV) I^(-) The correct order of increasing leaving group capability of above anions

Nucleophilic substitution reactions generally expressed as Nu^(-) +R-L rarr R-Nu +L^(-) Where Nu^(-) rarr Nucleophile , R-L rarr substrate, L rarr leaving group The best leaving groups are those that become the most stable ions after they depart. since most leaving group leave as a negative ion, the best leaving groups are those ions that stabilize a negative charge most effectively. A good leaving group should be (a) electron-withdrawing to polarize the carbon (b) stable once it has left (not a strong base) (c) polarise able to maintain partial bonding with the carbon in the transition state (both S_(N)1 and S_(N)2) . This bonding helps to stabilise the transition state and reduces the activation energy. (I) CH_(3)Br (II) CH_(3)F (III) CH_(3)OH (IV) CH_(3)OSO_(2)CF_(3) The correct order of decreasing reactivity of the above compounds towards CH_(3)O^(-) in an S_(N)2 reaction is: