Home
Class 11
MATHS
A=(2,3,5), B(-1,3,2), C=(lambda,5,mu) ar...

`A=(2,3,5), B(-1,3,2), C=(lambda,5,mu)` are the vertices of a triangle. If the median AM is equally inclined to the coordinate axes, then `(lambda,mu)`=

A

(10,7)

B

(1,1,1)

C

(0,1,1)

D

(1,1,0)

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • DOT PRODUCT OF TWO VECTORS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|57 Videos

  • DOT PRODUCT OF TWO VECTORS

    AAKASH SERIES|Exercise EXERCISE - I|30 Videos

  • DIRECTION COSINES AND RATIOS

    AAKASH SERIES|Exercise ADVANCED SUBJECTIVE TYPE QUESTIONS|8 Videos

  • ERRORS AND APPROXIMATIONS

    AAKASH SERIES|Exercise ADVANCED SUBJECTIVE TYPE QUESTION|15 Videos

Similar Questions

Explore conceptually related problems

Let A (2,3,5) , B ( -1,3,2) and C( lambda ,5, mu ) be the vertices of a Delta ABC , If the median through A is equally inclined to the coodinate axes, then

Let ABC be a triangle with vertices at points A( 2,3,5 ), B ( -1,3,2) and ( lambda , 5, mu ) in three dimensional space. If the median through A is equally inclined with the axes , then (lambda , mu ) is equal to

ABC is a triangle in a plane with vertices A(2, 3, 5), B(-1, 3, 2) and C(lambda, 5, mu) . If the median through A is equally inclined to the coordinate axes, then the value of (lambda^(3)+mu^(3)+5) is:

Let ABC be a triangle with A(alpha, 5, beta), B(-2,1,6) and C(1, 0, -3) as its vertices. If the median through B is equally inclined to the coordinate axes, then alpha+beta=

Show that (5,3),(1,2) and (-3,1) are the vertices of an isosceles triangle.

If A = (3, 2, 5), B = (3, 3, 5) and C = (3, 4, 8) are the vertices of a triangle ABC, then its centroid is

If A (1,2,3) , B(0,1,2) and C (2,1,0) are vertices of a triangle , then the length of the median through A is

Let A (4, 2), B(6, 5) and C(1, 4) be the vertices of DeltaABC . AD is the median on BC. Find the coordinates of the point D.

AAKASH SERIES-DOT PRODUCT OF TWO VECTORS-EXERCISE - II
  1. The value of 'x' for which the angle between bara=2x^(2)bari+4barxj+ba...

    Text Solution

    |

  2. A vector bara of magnitude 50 is collinear with the vector 6bari -8bar...

    Text Solution

    |

  3. A=(2,3,5), B(-1,3,2), C=(lambda,5,mu) are the vertices of a triangle. ...

    Text Solution

    |

  4. The vector bara,barb,barc are equal in length and pair wise make equal...

    Text Solution

    |

  5. Find unit vector orthogonal to the vector 3bari + 2barj + 6bark and co...

    Text Solution

    |

  6. If bara=4bari+5barj-bark, barb=bari-4barj+5bark, barc=3bari+barj-bark ...

    Text Solution

    |

  7. If barp=(3,-1,5), barq = (1,2,-3). A vector barr is such that it is ...

    Text Solution

    |

  8. If bara,barb,barc " are unit vectors, then " abs(bara-barb)^(2)+abs(ba...

    Text Solution

    |

  9. If kbara = 3barb+2barc, bara=-2barb+5barc " and if " barb and barc hav...

    Text Solution

    |

  10. bara,barb,barc and bard are the position vectors of four coplanar poin...

    Text Solution

    |

  11. In a Delta ABC, bar(OA)= bara, bar(OB)=barb, bar(OC) = barc. if (bar...

    Text Solution

    |

  12. ABC is an equitateral triangle of side 'a'. Then bar(AB).bar(BC)+bar...

    Text Solution

    |

  13. In Delta ABC , angleABC=90^(@). If P and Q are points of trisection o...

    Text Solution

    |

  14. A parallogram constructed on the vector bar(a) =3barp-barq and bar(b)...

    Text Solution

    |

  15. The length of the projection of the vector (1,-2,-1) on the vector joi...

    Text Solution

    |

  16. The magnitude of the projection of the vector bara=4bari-3barj+2bark o...

    Text Solution

    |

  17. If barb=4bari+3barj and barc be two perpendicular vectors in xy-plane....

    Text Solution

    |

  18. Let bara = 2bari -barj+bark , barb=bari+2barj-bark , barc=bari+barj-2b...

    Text Solution

    |

  19. The triangle ABC is defined by the vertices A =(0,7,10), B = (-1,6,6) ...

    Text Solution

    |

  20. In the Parallelogram ABCD, bar(AC)^(2)-bar(BD)^(2) =

    Text Solution

    |