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If (CosA)/(CosB)=nand(SinA)/(SinB)=m th...

If `(CosA)/(CosB)=nand(SinA)/(SinB)=m` then `(m^(2) - n^(2)) Sin^(2) B` =

A

`1 - n^(2)`

B

`1 + n^(2)`

C

1 -n

D

1 + n

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The correct Answer is:
A
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