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The line x/a-y/b=1 meets the X-axis at P...

The line `x/a-y/b=1` meets the X-axis at P. Find the equation of the line perpendicular to this line at P.

Text Solution

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The correct Answer is:
`ax+by+a^(2)`
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Knowledge Check

  • The line x/a+y/b=1 cuts the coordinate axes at a and B a line perpendicular to AB meets the axes in P and Q. The equation of the locus of the point of intersection of the lines AQ and BP is

    A
    `x^(2)+y^(2)=a^(2)+b^(2)`
    B
    `x^(2)+y^(2)=a^(2)`
    C
    `x^(2)+y^(2)-ax-by=0`
    D
    `x^(2)+y^(2)+ax+by=0`

  • The line x+y=1 cuts the coordinate axes at P and Q and a line perpendicular to it meet the axes R and S. The equation to the locus of the intersection of lines PS and QR is

    A
    `x^(2)+y^(2)=1`
    B
    `x^(2)+y^(2)-2x-2y=0`
    C
    `x^(2)+y^(2)-x-y=0`
    D
    none

  • A straight line (x)/(a)+(y)/(b)=1 meets the axes in A, B.A line perpendicular to AB meets the axes in P and Q. The locus of point intersection of AQ and BP is

    A
    `x(x-a)+y(y-b)=0 `
    B
    `x(x+a)+y(y+b)=0`
    C
    `x(x+a)+y(y-b)=0`
    D
    `x(x-a)+y(y+b)=0`

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