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Transform the equation x/a+y/b=1 into no...

Transform the equation `x/a+y/b=1` into normal form where `agt0, bgt0`. If the perpendicular distance of the straight line from the Origin is p then deduce that `1/(p^(2))=1/(a^(2))+1/(b^(2))`

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The correct Answer is:
`(bx)/(sqrt(a^(2)+b^(2)))+(ay)/(sqrt(a^(2)+b^(2)))=(ab)/(sqrt(a^(2)+b^(2)))`
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