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Show that the lines 2x+y-3=0, 3x+2y-2=0 ...

Show that the lines` 2x+y-3=0, 3x+2y-2=0` and `2x-3y-23=0` are concurrent and find the point fo concurrency.

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The correct Answer is:
(4,-5)
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Knowledge Check

  • If the lines 4x+3y-1=0, x-y+5=0 and kx+5y-3=0 are concurrent, then k =

    A
    4
    B
    5
    C
    6
    D
    7

  • If the lines 2x+y-1=0,ax+3y-3=0,3x+2y-2=0 are concurrent then a=

    A
    4
    B
    0
    C
    `-4`
    D
    Any real number

  • If the lines 7x+2y-8=0, 2x+y-1=0, 3x+4y+6=0 are concurrent, then the point of concurrence is

    A
    (2, -3)
    B
    (6, 11)
    C
    `(78//47, -181//47)`
    D
    `(-13//5,2//5)`

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