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A straight line through origin O meets t...

A straight line through origin O meets the lines `3y=10-4x` and `8x+6y+5=0` at points A and B respectively. Then O divides the segment AB in the ratio.

A

`2:3`

B

`1:2`

C

`4:1`

D

`3:4`

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-STRAIGHT LINES-PRACTICE EXERCISE
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  17. The base of an equilateral triangle is along the line given by 3x+4y=9...

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