Home
Class 11
MATHS
The D.R's of a normal to the planes are ...

The D.R's of a normal to the planes are 1, 2, 3 and distance of plane from (0, 0, 0) is 5, then equation of plane is :

A

`x+2y+3z=5sqrt(14)`

B

`x-2y+3z=3sqrt(2)`

C

`x-2y+3z=5sqrt(14)`

D

`x+2y+3z=3sqrt(11)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

If the foot of the perpendicular from (0, 0, 0) to a plane is (1, 2, 3), then the equation of the plane is

The d.c.'s of the normal to the plane 2x + 3y – 6z + 5 = 0 are

If the foot of the perpendicular from (0,0,0) to a plane is (1, 2, 2), then the equation of the plane is

The d.r's of the normal to the plane passing through the point (2,1,3) and the line of intersection of the planes x+2y+z=3 and 2x-y-z=5 is

Find d.c's of the normal to plane 3x - 6y +2z -4 = 0

A vector barn is inclined to x-axis at 45^(0) , to y-axis at 60^(0) and at an acute angle to z-axis. If barn is a normal to plane passing through the point (sqrt(2),-1, 1) , then the equation of plane is :

A vector vecn is inclined to x-axis at 45^(0) , to y-axis at 60^(0) and at an acute angle to z-axis. If vecn is a normal to a plane passing through the point (sqrt(2), -1, 1) , then the equation of the plane is :