Home
Class 11
MATHS
If the length of a simple pendulum is de...

If the length of a simple pendulum is decreased by 2%, find the percentage error in its period T.

Text Solution

Verified by Experts

The correct Answer is:
-1
Promotional Banner

Topper's Solved these Questions

  • ERRORS AND APPROXIMATIONS

    AAKASH SERIES|Exercise EXERCISE - 5.1 (VERY SHORT ANSWER QUESTION)|17 Videos
  • DOT PRODUCT OF TWO VECTORS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|57 Videos
  • FUNCTIONS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|50 Videos

Similar Questions

Explore conceptually related problems

If the length of a simple pendulum is decreased by 3%, then the percentage error in its period T is

Assertion (A): If the length (l) of the simple pendulum is decreased by 4 % then decrease in its time period (T) is 2 % Reason (R) : If y=x^(n) , ratio of percentage errors in y and x is 1:n The correct answer is

If the period of oscillation of a simple pendulum is increased by a% then the percentage increase in its length is

If PV^(1//4)=C , then the volume is decreased by 1/2% then the percentage error in P is

If there is an error of 2% in measuring its length, of a simple pendulum then the percentage error in the period will be

The error in the measurement of the length of a simple pendulum is 0.1% and the error in the time period is 2%. What is the possible percentage of error in the physical quantity having the dimensional formula LT^(-2) .