If theta is eliminated from the equation...

If `theta` is eliminated from the equations `x=a cos(theta-alpha)` and `y=b cos(theta-beta)`, then `x^(2)/a^(2) + y^(2)/b^(2) -(2xy)/(ab) cos(alpha-beta)` is equal to:

A

`sec^(2)(alpha - beta)`

B

`"cosec"^(2)(alpha - beta)`

C

`cos^(2)(-beta)`

D

`sin^(2)(alpha - beta)`

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The correct Answer is:

D

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