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If cos(theta - alpha)=a, cos(theta-beta)...

If `cos(theta - alpha)=a, cos(theta-beta)=b`, then `sin^(2)(alpha -beta) + 2abcos(alpha-beta)=0`

A

`a^(2) + b^(2)`

B

`a^(2)-b^(2)`

C

`b^(2)-a^(2)`

D

`-a^(2) - b^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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