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If cot^(2)x =cot(x-y) cot(x-z), then cot...

If `cot^(2)x =cot(x-y) cot(x-z)`, then cot(2x) is equal to (where `x ne +-pi/4`)

A

`(cotx + coty)/2`

B

`(cot y + cotz)/2`

C

`(cotx + cotz)/2`

D

`(cotx - cot z)/2`

Text Solution

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The correct Answer is:
B
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