If tantheta = ntan phi then the maximum...

If `tantheta = ntan phi` then the maximum value of `tan^(2)(theta - phi)` is equal to

A

`(n+1)^(2)/(4n)`

B

`(n-1)^(2)/(4n)`

C

`(n+1)^(2)/(2n)`

D

`(n-1)^(2)/(2n)`

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The correct Answer is:

B

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