The sum of the series, sin theta sec(3th...

The sum of the series, `sin theta sec(3theta)+sin 3theta sec(3^(2)theta)+sin(3^(2)theta)sec(3^(3)theta)+…….` upto n terms, is

A

`1/2[tan3^(n)theta - tan3^(n-1)theta]`

B

`[tan3^(n)theta - tan theta]`

C

`1/2[tan3^(n)theta - tan theta]`

D

`1/2(tan3^(n)theta-1)`

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The correct Answer is:

A

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