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If tan theta = n tan phi then the maximu...

If `tan theta = n tan phi` then the maximum value of `tan^(2)(theta-phi)` is equal to

A

`((n+1)^(2) )/( 2n)`

B

`((n+1)^(2) )/( n)`

C

`((n+1)^(2) )/(2)`

D

`((n+1)^2)/( 4n)`

Text Solution

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The correct Answer is:
D
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