A tyre company is able to manufacture `x` (hundred) grade `A` tyres and y (hundred) grade `B` tyres per day, where `y(5-x) = 10(4 - X), 0 le x le 4.` If the profit oneach grade A tyre is twice the profit on grade B tyre,what is the most profitable number of grade A tyresper day to manufacture?

A tyre company is able to manufacture x (hundred) grade A tyres and y (hundred) grade B tyres per day,where y(5-x)=10(4-X),0<=x<=4. If the profit oneach grade A tyre is twice the profit on grade B tyre,what is the most profitable number of grade A tyresper day to manufacture?

A manufacturer produces two types of soaps using two machines A and B . A is operated for 2 minutes and B for 3 minutes to manufacture first type , while it takes 3 minutes on machine A and 5 minutes on machine B to manufature second type . Each machine can be operated at the most for 8 hours per day . The two types of soap are sold at a profit of Rs 0.25 and Rs 0.05 each respectively . Assuming that the manufactured can sell all the soaps he can manufacture , how many soaps of each type should be manufature per day so as to maximize his profit .

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the maximum profit which can manufacturer earn?

The profit function P(x) of a firm, selling x items per day is given by P(x)= (150-x)x-1625 . Find the number of items the firm should manufacture to get maximum profit. Find the maximum profit

Maximum profit: A barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: When no barrels are produce what is a profit loss?

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the profit/loss if 175 barrels are produced

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the profit/loss if 400 barrels are produced

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the break even point ? (Zero profit point is called break even)