Twenty metres of wire is available for fencing off a flower-bed in the form of a circular sector. Then the maximum area (in `s qdotm)` of the flower-bed is: 25 (2) 30 (3) 12.5 (4) 10

Twenty metres of wire is available for fencing off a flower-bed in the form of a circular sector.Then the maximum area (in sq.m) of the flower-bed is: 25 (2) 30 (3) 12.5 (4) 10

Twenty meters of wire is available for fencing a flower -bed in the form of a circular sector .Then the maximum area in square meters of the flower bed is

Three plots having areas 110,130 and 190 square metres are to be subdivided into flower beds of equal size.If the breadth of a bed is 2 metre,the maximum length of a bed can be (a) 5mquad (b) 11m (c) 13m (d) 19m

A square lawn with side 100 m long has a circular flower bed in the centre. If the area of the lawn, excluding the flower bed, is 8614 m2, the radius of the circular flower bed is (a) 21 m (b) 31 m (c) 41 m (d) None of these

Find maximum possible area that can be enclosed by a wire of length 20cm by bending it in form of a circular sector. 10 (b) 25 (c) 30 (d) 20

In each of the corners, there is a flower bed in the form of a quadrant of a circle of radius 2 m. Also, there is a flower bed in the form of a circle of radius 2 m in the middle of the plot. Find the area of the remaining plot.

Maximum possible area that can be enclosed by a wire of length 20cm by bending it in form of a circular sector is 10b.25c.30d.20

A copper wire of length 36 m and diameter 2 mm is melted to form a sphere. The radius of the sphere (in cm) is (a) 2.5 (b) 3 (c) 3.5 (d) 4

Shown below is the top view of a stadium. There is a badminton court at the centre. The stadium is surrounded by a jogging track. The track is semi-circular in shape at the top and the bottom of the court. The fountains converge at the centre of the respective semicircles. The jogging track has a uniform width of 2 m. The cost of gardening is Rs 300/ m^(2) and the area of the fountain next to the flower bed is 150 m^(2) . What is the cost of gardening the flower bed?

A square park has each side of 100 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 14 m as shown in Fig. 15.37. Find the area of the remaining part of the park (U s e pi=22//7) . (FIGURE)