10g of non-volatile solute when dissolved in 100g of benzene raises its boiling point by `1^@` C. What is the molecular mass of the solute. (`k_b` for benzene=2.53 K kg `mol^-1`)

Boiling point of benzene is 353.23 K . When 1 . 80 g of non-volatile solute was dissolved in 90 g of benzene the boiling point is raised to 354. 11 K? Calculate molar mass of solute . ( K_(b) for benzene is 2 . 53 K kg mol^(-1) )

The boiling point of benzene is 353.23 K. When 1.80g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute.

The boiling point of Benzene (C_(6) H_(6)) is 353.23 K. When 1 . 80 g of a non - volatile solute was dissolved in 90 g of C_(6) H_(6) the boiling point is raised to 354 . 11 K. Calculate the molar mass of solute . (Given K_(b) for benzene is 2 . 53 K kg mol^(-1) )

A solution containing 2.44 g of solute dissolved in 75 g of water boiled at 100.413^@C . What will be the molar mass of the solute?

15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0 . 34^(@) C . What is them molar ass of the substance ? ( K_(f) for water = 1. 86 K kg mol^(-1) )

A solution prepared by dissolving 1.25g of oil of winter green (methyl salicylate) in 99.0 g of benzene has a boiling point of 80.31^@C . Determine the molar mass of this compound. (B.P of pure benzene= 80.10^@C and K_b for benzene= 2.53^@C kg mol^-1 ).

3.0 g of non-volatile solute when dissolve in 1 litre water, shows an osmotic pressure of 2 atmosphere at 300 K. Calculate the molar mass of the solute. (R = 0.0821 litre atm K^(-1)"mol"^(-1) ).

A solution containing 12.5 g of a non- electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of the substance ( K_b for water = 0.52 K kg mol^(-) ).