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Transition metals form number of interst...

Transition metals form number of interstitial compounds. Explain.

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Transition metals form large number of complex compounds.Explain.

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Transition metals, when they form interstitial compounds, the non-metals (H,B,C,N) are accommodated in:

Transition metals form mostly coloured compounds.Explain.

Transition metals form alloys with other transition metals. Explain.

Why transition elements form a number of alloys ?

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The transition metals and many of their compounds show paramagnetic behaviour. Explain why ?

JMD PUBLICATION-SAMPLE QUESTION-EXAMPLE
  1. Which form of sulphur shows paramagnetic behaviour and why ?

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  2. Compare and explain bond angles of H2O and H2S

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  3. Transition metals form number of interstitial compounds. Explain.

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  4. Why are Min^(2+) compounds more stable than Fe^(2+) towards oxidation ...

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  5. What is meant by unidentate, didentate and ambidentate ligands ? Give ...

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  6. [Fe(CN)6)]^(4-) and [Fe(H2O)6)]^(2+) are of different colours in di...

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  7. Explain the factors affecting rate of a reaction.

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  8. Calculate the potential of hydrogen electrode income with a solution w...

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  9. Compare and explain the reactivity of different alcohols towards sodiu...

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  10. Why is phenol stronger acid than the alcohols ? Explain in detail.

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  11. Show that the time required for 99% completion of a first order reacti...

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  12. A first order reaction takes 40 min for 30% completion. Calculate t(1/...

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  13. Why is dioxygen gas but sulphur a solid?

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  14. Most of the compounds of transition elements are paramagnetic in natur...

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  15. Why do transition metals have high enthalpies of atomization ?

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  16. Transition metals form mostly coloured compounds.Explain.

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  17. Transition elements and their compounds are found to be good catalysts...

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  18. Why Cr^(2+) is strongly reducing while Mn^(3+) is strongly oxidising ?

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  19. The d^1 configuration is very unstable in transition metal ions. Exp...

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  20. What happens when : n-butyl chloride is treated with alcoholic KOH.

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