Write the amplitude and phase difference for all particles of same interval for stationary waves.

What will be the phase difference of particles in successive intervals of stationary waves ?

Explain about amplitude and phase of wave.

The motion of a particle executing simple harmonic motion is described by the displacement function, x(t)=Acos(omegat+phi) . If the initial (t = 0) position of the particle is 1 cm and its initial velocity is omega cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is pi s^(-1) . If instead of the cosine function, we choose the sine function to describe the SHM : x = B sin (omegat + alpha) , what are the amplitude and initial phase of the particle with the above initial conditions.

The linear variable of all particles are same in rotational motion of rigid body.

Three waves producing displacement in the same direction of same frequency and of amplitudes 10etam, 4etam" and "7eta m arrive at a point with successive phase difference of pi//2 . The amplitude of the resultant wave is :--

If in a stationary wave the amplitude corresponding to antinode is 4 cm, then the amplitude corresponding to a particle of medium located exactly midway between a node and an antinode is :-

Explain clearly, with examples, the distinction between : (a) magnitude of displacement (sometimes called distance) over an interval of time, and the total length of path covered by a particle over the same interval, (b) magnitude of average velocity over an interval of time, and the average speed over the same interval. (Average speed of a particle over an interval of time is defined as the total path length divided by the time interval]. Show in both (a) and (b) that the second quantity is either greater than or equal to the first. When is the equality sign true ? (For simplicity, consider onedimensional motion only).

In the wave propagation phenomenon, phase difference of oscillation of two particles having distance à from each other is ......