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A source whistling a sound of frequency 450 Hz moves towards a stationary listener with a speed of 33 m/s. If velocity of sound is 333 m/s, then find frequency of sound heard by this listener.

A

409

B

429

C

517

D

500`

Text Solution

Verified by Experts

The correct Answer is:
D

We have, `(f _(L))/( v + v _(L)) = (f _(S))/( v + v _(S))`
`therefore ( f _(L))/( 333 + 0) = (450)/(333-33)`
`therefore f _(L) = 450 xx (333)/(300)= 499.5Hz ~~ 500Hz`
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