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For a stationary wave y = 10 sin ((pi x ...

For a stationary wave `y = 10 sin ((pi x )/(4)) cos (2pi t )` metre, distance between two consecutive nodes is ...... m.

A

4

B

2

C

1

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
Comparing given equation with `y = 2a sin (kx) cos (omega t), ` we get `k = (pi)(4)`
`therefore (2pi)/(lamda) = (pi)/(4) implies lamda = 8 m`
Required distance `= (lamda)/(2) = (8)/(2) = 4 m`
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