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Along the direction of propagation of on...

Along the direction of propagation of one wave of frequency 120 Hz, phase difference between two particles separated by 1 m distance is `90^(@)`. Find velocity of this wave.

A

`180 m//s`

B

`240 m//s`

C

`480 m//s`

D

`720 m//s`

Text Solution

Verified by Experts

The correct Answer is:
C

We know that, `Delta phi = (2pi )/(lamda ) (Delta x )`
`therefore Delta phi = (2pi f )/(v ) (Delta c ) " "(because v= f lamda )`
`therefore (pi)/(2) = (2 pi xx 120)/(v) (1)`
`therefore v = 480 m//s`
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