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KUMAR PRAKASHAN-OBJECTIVE SECTION AS PER NEW PAPER SCHEME -Linear in Equalities (True/False Statement)
- For x in N solution set of x +2 lt -8 is null set.
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Playing Now - Inequality 3(x-1) + 2 (x-2) lt 5 (x +2) is true for each x in R .
01:23
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Play - Solution set of x ge 3 and x le 5 , x in R is [3,5]
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Play - Graph of inequality x - 3 lt 5 and 3x + 5 lt 2 x in R is as follows
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Play - If |x - 2| lt 3 then -1 lt x lt 5.
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Play - If (1)/(x-4) lt 0 then x gt 4.
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Play - Solution set of inequality |x-1| lt -1 is set R .
01:16
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Play - For x in N solution set of x +2 lt -8 is null set.
01:23
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Play - Inequality 3(x-1) + 2 (x-2) lt 5 (x +2) is true for each x in R .
01:29
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Play - Solution set of x ge 3 and x le 5 , x in R is [3,5]
01:49
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Play - Graph of inequality x - 3 lt 5 and 3x + 5 lt 2 x in R is as follows
02:11
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Play - If |x - 2| lt 3 then -1 lt x lt 5.
01:15
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Play - If (1)/(x-4) lt 0 then x gt 4.
00:44
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Play - Solution set of inequality |x-1| lt -1 is set R .
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