Home
Class 11
MATHS
Radius of the circle x^2+y^2+8x+10y=8 is...

Radius of the circle `x^2+y^2+8x+10y=8` is 7 unit.

Text Solution

Verified by Experts

The correct Answer is:
True Statement
Promotional Banner

Topper's Solved these Questions

  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Introduction to Three Dimensional Geometry (Fill in the Blanks)|24 Videos
  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Introduction to Three Dimensional Geometry (True/False Statement)|16 Videos
  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Conic Sections (Fill in the blanks )|52 Videos
  • MATHEMATICAL REASONING

    KUMAR PRAKASHAN|Exercise QUESTION OF MODULE (Knowledge Test:)|2 Videos
  • PERMUTATIONS AND COMBINATIONS

    KUMAR PRAKASHAN|Exercise PRACTICE WORK |40 Videos

Similar Questions

Explore conceptually related problems

Find the centre and the radius of the circle x^(2)+y^(2)+8x+10y-8=0 .

Line y = 2x I chord of the circle x^(2) + y^(2) - 10x = 0 . Derive equaiton of the circle whose diameter is chord.

In each the following find the centre and radius of circles. x^(2)+y^(2)-8x+10y-12=0 .

Find equation of circle whose end points of diameter are centres of the circle x^(2) + y^(2) + 6x - 14y - 1 =0 and x^(2) + y^(2) - 4x + 10y - 2 = 0 .

Obtain centre and radius of the circle given by x^(2) + y^(2) + 6x + 8y - 75 = 0 .

The shortest distance from the point (2,-7) to the circle x^(2) + y^(2) - 14x - 10y - 151 = 0 is equal to 5.

Find the area lying above x-axis and included between the circle x^2 +y^2 = 8x and inside of the prarabola y^2 = 4x .

Prove that the centres of the circle x^(2) + y^(2) - 4x - 2y + 4 = 0, x^(2) + y^(2) - 2x - 4y + 1 = 0 and x^(2) + y^(2) + 2x - 8y + 1 = 0 are collinear. More over prove that their radii are in geometric pregression.

The line x + 3y = 0 is a diameter of the circle x^(2) + y^(2) + 6x + 2y = 0 .

Let S be the focus of the parabola y^2=8x and let PQ be the common chord of the circle x^2+y^2-2x-4y=0 and the given parabola. The area of the triangle PQS is -

KUMAR PRAKASHAN-OBJECTIVE SECTION AS PER NEW PAPER SCHEME -Conic Sections (True /False Statement)
  1. Radius of the circle touches X - axis = |x co - ordinate of centre |.

    Text Solution

    |

  2. Radius of the circle x^2+y^2+8x+10y=8 is 7 unit.

    Text Solution

    |

  3. Eccentricity of curve given equation y^2=9x is 1.

    Text Solution

    |

  4. Equation of directrix of parabola 2y^2=x is 8x + 1 = 0

    Text Solution

    |

  5. Semi vertical angle of cone is alpha . Plane intersects vertical axis ...

    Text Solution

    |

  6. Ellipse x^2/(25)+y^2/(9) =1 is symmetric about Y - axis.

    Text Solution

    |

  7. (5,10) and (5,-10) are end points of latus rectum of parabola y^2 = 20...

    Text Solution

    |

  8. t in R parametric equation of parabola are x=at^2 and y = 2at .

    Text Solution

    |

  9. Length of latus rectum of ellipse is (x^2)/b^2+y^2/a^2 = .......... 1 ...

    Text Solution

    |

  10. Equation x = 4 cos theta and y = 3 sin theta , theta in (-pi,pi) deno...

    Text Solution

    |

  11. Curve having eccentricity sqrt2 is a rectangular hyperbola.

    Text Solution

    |

  12. Radius of the circle touches X - axis = |x co - ordinate of centre |.

    Text Solution

    |

  13. Radius of the circle x^2+y^2+8x+10y=8 is 7 unit.

    Text Solution

    |

  14. Eccentricity of curve given equation y^2=9x is 1.

    Text Solution

    |

  15. Equation of directrix of parabola 2y^2=x is 8x + 1 = 0

    Text Solution

    |

  16. Semi vertical angle of cone is alpha . Plane intersects vertical axis ...

    Text Solution

    |

  17. Ellipse x^2/(25)+y^2/(9) =1 is symmetric about Y - axis.

    Text Solution

    |

  18. (5,10) and (5,-10) are end points of latus rectum of parabola y^2 = 20...

    Text Solution

    |

  19. t in R parametric equation of parabola are x=at^2 and y = 2at .

    Text Solution

    |

  20. Length of latus rectum of ellipse is (x^2)/b^2+y^2/a^2 = .......... 1 ...

    Text Solution

    |