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Three rings each of mass M and radius R ...

Three rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY¢ will be

A

`3MR^(2)`

B

`(3)/(2)MR^(2)`

C

`5MR^(2)`

D

`(7)/(2)MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
M.I of system about YY. `I=I_(1)+I_(2)+I_(3)`
where `I_(1)` = moment of inertia of ring about diameter `l_(2)=l_(3)` = M.I. of inertia of ring about a tangent in a plane
`therefore I=(1)/(2)mR^(2)+(3)/(2)mR^(2)+(3)/(2)mR^(2)=(7)/(2)mR^(2)`
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Knowledge Check

  • Three rings each of mass M and radius R are arranged as shown in the figure . The moment of inertia of the system about AB is (NAR_NEET_PHY_XI_P2_C07_E11_036_Q01.png" width="80%">

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    D
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