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Three point masses each of mass m are pl...

Three point masses each of mass m are placed at the corners of an equilateral triangle of side 'a'. Then the moment of inertia of this system about an axis passing along one side of the triangle is

A

`ma^(2)`

B

`3ma^(2)`

C

`(3)/(4)ma^(2)`

D

`(2)/(3)ma^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
The moment of inertia of system about AB side of triangle
`I=I_(A)+I_(B)+I_(C)`
`=0+0+mx^(2)`

`=m((asqrt(3))/(2))^(2)=(3)/(4)ma^(2)`
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