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The moment of inertia of HCl molecule ab...

The moment of inertia of `HCl` molecule about an axis passing through its centre of mass and perpendicular to the line joining the `H^+` and `Cl^-` ions will be (if the inter atomic distance is `1A^@`)

A

`0.61xx10^(-47)kg.m^(2)`

B

`1.61xx10^(-47)kg.m^(2)`

C

`0.061xx10^(-47)kg.m^(2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
If `r_(1)` and `r_(2)` are the respective distances of particles `m_(1)` and `m_(2)` from the centre of mass then
`m_(1)r_(1)=m_(2)r_(2)implies1xx x=35.5xx(L-x)impliesx=35.5(1-x)`
`impliesx=0.973ÅandL-x=0.027Å`
Moment of inertia of the system about centre of mass `I=m_(1)x^(2)+m_(2)(L-x)^(2)`
`I=1"amu"xx(0.973Å)^(2)+35.5"amu"xx(0.027Å)^(2)`
Substituting 1 a.m.u. = `1.67xx10^(-27)kg and 1Å=10^(-10)m`
`l=1.62xx10^(-47)kgm^(2)`
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