Home
Class 11
PHYSICS
A fly wheel of M.I. 0.32 kg m^(2) is rot...

A fly wheel of M.I. `0.32 kg m^(2)` is rotated steadily at 120 rad/s by 50 w electric motor. Then the value of the frictional couple opposing rotation is,

A

4608J

B

1152J

C

2304J

D

6912J

Text Solution

Verified by Experts

The correct Answer is:
C
Kinetic energy `K_(R )= (1)/(2) I omega^(2)= (1)/(2) (0.32) (120)^(2)= 2304J`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on centre of mass)|12 Videos

  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on angular displacement, velocity and acceleration)|16 Videos

  • NEWTONS LAWS OF MOTION

    ERRORLESS |Exercise Self Evaluation Test|16 Videos

  • SIMPLE HARMONIC MOTION

    ERRORLESS |Exercise simple Harmonic Motion|21 Videos

Similar Questions

Explore conceptually related problems

A flywheel of moment of inertia 5.0 kg m^2 is rotated at a speed of 60 rad/s. Because of the frictionat te axle, it comes to rest in 5.0 minutes. Find a. The average torque of the friction. B. the total work done by the friction and c. the angular momentum of the wheel 1 minute before it stops rotating.

A fly wheel of M.I. 6xx10^(-2) kgm^(2) is rotating with an angular velocity of 20 rad s^(-1) . The torque required to bring it to rest in 4s is

A flywheel of moment of inertia 5.0kg-m^(2) is rotated at a speed of 10rad//s because of the friction at the axis it comes to rest in 10s. Find the average torque of the friction.

A whel of M.I. = 1 kg-m^(2) is rotating at an angular speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minute. What is the angular momentum of the wheel in kg m^(2)//s two minutes before it comes to rest ?

A disc of moment of inrtia 20 kg . m^(2) is rotated about its transverse symmetry axis at 120 rpm by an electric motor of power 62.84 watts. When the motor is switched off, how many rotations does it complete before coming to rest ?

A wheel with moment of inertia 10 kg m^(2) is rotating at (2//pi) rps on its axis. The frictional torque acting on it, if it makes 20 rotations befor stopping is

A flywheel of moment of inertia 2 "kg-m"^(2) is rotated at a speed of 30 "rad/s" . A tangential force at the rim stops the wheel in 15 second. Average torque of the force is

A wheel having moment of inertia 12 kg m^(2) about its axis, rotates at 50 rpm about this axis.Then the torque that can stop the wheel in one minute is in (SI units) is (pi)/(N) .Then the value of N is ?

A flywheel of moment of inertia 10kg m^(2) is rotating at 50 rad//s . It must be brought to stop in 10 s . (a) How much work must be done to stop it? (b) What is the required average power?

A wheel at rest has M.I. 2/(pi^2) kgm^2 . It is rotated by a 60W motor for one minute. The number of rotations made by the wheel in one minute is