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A cord is wound round the circumference ...

A cord is wound round the circumference of wheel of radius `r`. The axis of the wheel is horizontal and fixed and moment of inertia about it is `I`. A weight `mg` is attached to the end of the cord and falls from rest. After falling through a distance `h`, the angular velocity of the wheel will be.

A

`sqrt((2gh)/(I + mr))`

B

`sqrt((2mgh)/(I + mr^(2)))`

C

`sqrt((2mgh)/(I+ 2mr^(2)))`

D

`sqrt(2gh)`

Text Solution

Verified by Experts

The correct Answer is:
B
According to law of conservation of energy `mgh= (1)/(2) (I + mr^(2)) omega^(2) rArr omega= sqrt((2mgh)/(I + mr^(2)))`
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