Home
Class 11
PHYSICS
If a bomb is thrown at a certain angle w...

If a bomb is thrown at a certain angle with the horizontal and after exploding on the way the different fragments move in different directions then the centre of mass

A

Would move along the same parabolic path

B

Would move along a horizontal path

C

Would move along a vertical line

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the motion of a bomb thrown at an angle and its explosion affecting the fragments, we will analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding the Initial Motion:** - When the bomb is thrown at an angle, it follows a parabolic trajectory due to the influence of gravity. The center of mass of the bomb follows this path until the explosion occurs. **Hint:** Remember that the trajectory of a projectile is a parabola when only gravity acts on it. 2. **Explosion of the Bomb:** - At some point during its flight, the bomb explodes. This explosion causes the bomb to break into several fragments, which then move in different directions. **Hint:** Consider the nature of the forces involved. The explosion is an internal force acting on the fragments. 3. **Effect of Internal Forces on Center of Mass:** - The key point to note is that the explosion is caused by internal forces. According to the principle of conservation of momentum, internal forces do not affect the overall motion of the center of mass of the system. **Hint:** Recall that internal forces (like those during an explosion) do not change the center of mass of a system. 4. **Center of Mass After the Explosion:** - Even after the explosion, the center of mass of the bomb (now fragments) will continue to move along the same parabolic path that it was following before the explosion. The position of the center of mass remains unchanged in the absence of external forces. **Hint:** Visualize the center of mass as a point that continues to follow the same trajectory, regardless of the individual movements of the fragments. 5. **Conclusion:** - Therefore, the center of mass of the bomb will continue to move along the same parabolic path after the explosion, even though the fragments are moving in various directions. **Hint:** The trajectory of the center of mass is independent of the individual motions of the fragments resulting from the explosion. ### Final Answer: The center of mass would move along the same parabolic path that it was following before the explosion.
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on angular displacement, velocity and acceleration)|16 Videos

  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on torque, couple)|11 Videos

  • ROTATIONAL MOTION

    ERRORLESS |Exercise Practice Problems (Problems based on motion of connected mass)|10 Videos

  • NEWTONS LAWS OF MOTION

    ERRORLESS |Exercise Self Evaluation Test|16 Videos

  • SIMPLE HARMONIC MOTION

    ERRORLESS |Exercise simple Harmonic Motion|21 Videos

Similar Questions

Explore conceptually related problems

A bomb is projected with speed 10 m/s at an angle 30 with the horizontal. In the mid-air bomb explodes in different fragments and they all move in different directions. At the time when all fragments reach at ground, the displacement of the center of mass of bomb from initial point will be (g = 10 m/s^2)

A bomb at rest explodes. The centre of mass

A ball is thrown with speed u at an angle theta with horizontally. After how much time it will move perpendicular to the initial direction of motion.

An object is thrown along a direction inclined at an angle of 45^(@) with the horizontal direction. The horizontal range of the particle is equal to

A body of mass m is thrown upwards at an angle theta with the horizontal with velocity v. While rising up the velocity of the mass after t second will be

A particle is projected from a point P with a velocity v at an angle theta with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particles is projected with speed u at an angle theta with horizontal particle explodes at highest point of its path into two equal fragments one of fragment moving up straighht with a speed u . The difference in time in which the particles fall on ground. (Assume it explodes at height H )

A projectile is fired with velocity. v_0 at an angle 60^@ with horizontal . At top of its trajectory it explodes into two fragments of equal mass. If one fragment retraces the path then the speed of the other fragment is

Statement I: If a ball projected up obliquely from the ground breaks up into several fragments in its path, the centre of the system of all fragments moves in the same parabolic path compared to initial one till all fragments are in air. Statement II: In the situation of Statement 1, at the instant of breaking, the fragments may be thrown in different directions with different speeds.