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A ball rolls without slipping. The radiu...

A ball rolls without slipping. The radius of gyration of the ball about about an axis passing through its center of mass is K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy be

A

`(K^(2))/(R^(2))`

B

`(K^(2))/(K^(2)+R^(2))`

C

`(R^(2))/(K^(2)+R^(2))`

D

`(K^(2)+R^(2))/(R^(2))`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is K, If radius of the ball be R, then the fraction of total energy associated with its rotational energy will be

    A
    `(K^(2))/(K^(2)+R^(2))`
    B
    `(R^(2))/(K^(2)+R^(2))`
    C
    `(K^(2)+R^(2))/(R^(2))`
    D
    `(K^(2))/(R^(2))`

  • A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is k . If radius of the ball be R , then the fraction of total energy associated with its rotation will be.

    A
    `(k^2 + R^2)/(R^2)`
    B
    `(k^2)/(R^2)`
    C
    `(k^2)/(k^2 + R^2)`
    D
    `(R^2)/(k^2 + R^2)`

  • A body rolls without slipping. The radius of gyration of the body about an axis passing through its centre of mass is K . The radius of the body is R . The ratio of rotational kinetic energy to translational kinetic energy is.

    A
    `(K^2)/(R^2)`
    B
    `(R^2)/(K^2 + R^2)`
    C
    `(K^2)/(K^2 + R^2)`
    D
    `K^2 + R^2`

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