3D Lattice Formation |Simple Cubic UnitCell#!#PYQs NEET/JEE

The vacant space in simple cubic lattice unit cell is :-

2-d Packing||Packing fraction||Simple cubic||bcc

Assertion (A) : Packing efficiency in simple cubic unit cell is 52.4% . Reason (R) : Density of the unit cell is given by the relation : d=(a^(3)N_(A))/(ZM) .

In a simple cubic lattice of anions, the side length of the unit cell is 2.88 Å . The diameter of the void in the body centre is

A metallic element crystallizes in simple cubic lattice. Each edge length of the unit cell is 3 Å.The density of the element is 8g//c c . Number of unit cells in 108 g of metal is

3D Crystal systems | Bravais Lattice | Crysyalline and Amorphous Solids | Types of Crystalline Solids | Lattice | Lattice Point and Unit Cell | 2D Crystal Systems Based Questions

Which of the following statements is /are correc ? I. For a simple cubic lattice , d= a and for fcc it is d=a//sqrt2 II. The density of the unit cell for cubic crystals for element is rho=(ZM)/(a^3N_Axx10^(-3)) gcm^(-3) III. In case of ionic compound A^+B^- having fcc structures as NaCl edge (a) = 2 x distance between A^+ " and " B^- ions .

Which of the following does not represent radius of the atom correctly ? (i)Simple cubic cell : Radius = a/2 (ii)Face centred cubic cell:Radius = a/(3sqrt3) (iii)Body centred cubic cell:Radius = sqrt3/4a